$e^{i\pi }+1=0$ [edit]

$\ln(i)/i=\pi /2$ [edit]

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e i π + 1 = 0 {\displaystyle e^{i\pi }+1=0} [edit]

ln ⁡ ( i ) / i = π / 2 {\displaystyle \ln(i)/i=\pi /2} [edit]

$e^{i\pi }+1=0$ [edit]

$\ln(i)/i=\pi /2$ [edit]