Talk:Lagrange inversion theorem

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What about this:

                ∞    dn-1  /  (w - a)n    \ |      (z - b)n 
   g(z) = a  +  ∑  ------ | -----------  | |      --------                      
               n=1 (dw)n-1 \ (f(w) - b)n  / |         n!
                                     | w=a

--Edmund 02:23 Feb 22, 2003 (UTC)

Yup, the TeX is correct now. AxelBoldt 20:45 Mar 2, 2003 (UTC)

Examples[edit]

I think the use of the "group" in binary tree example unnecessary complicates things. If I didn't know what this is all about I wouldn't have guessed what is meant here. Can someone rewrite this in plain language, like "removing the root splits a binary tree into two subtrees, so accounting for the missing root vertex we have..."

Also, while I am here - the example with enumeration of labeled trees giving Cayley's formula is much more interesting, I say. Mhym 23:14, 22 July 2006 (UTC)[reply]

Generalizations? How?[edit]

The article states that the theorem is readily generalized to functions of several variables, but I don't see how, not the least of which is because the dimensions of the domain need not be the same as the dimensions of the range (for example, a vector-valued function of a scalar would have what kind of series, or vice versa?).--Jasper Deng (talk) 06:03, 20 January 2014 (UTC)[reply]

Proof of the theorem is not given[edit]

The proof of the theorem is not to be found anywhere. Not even in Lagrange's original paper. — Preceding unsigned comment added by 2601:9:8180:1029:C5A7:2EC4:2CEB:1843 (talk) 18:19, 30 April 2014 (UTC)[reply]

You may check the link to the wiki article on formal power series, where a few lines elementary proof is given. --pma 14:07, 3 May 2014 (UTC)[reply]